Maths Tricks and Fun Lesson1
At the onset we will start with number 9. This number falls between number 8 and 10. It is an interesting number. Several names are attributed to it by mathematicians depending on its properties. In
nature several flowers , trees,shell of some snails all follow a pattern called fibonacci sequence. That is it increases in a pattern 1,1,2,3,5,8,13,21 like that.
When you multiply 9 with any number, and when you
add the digits of the product , the answer is 9, that is
the digital sum is always 9 in a multiplication with 9.
When you multiply 1 2 3 4 5 6 7 9 with 9 omitting 8
the answer is always111111111. The same number
when multiplied with 18, you get 222222222. Why because 9× 2 is 18.In the same way ,12345679 X 81
will give you 999999999. While I was doing some multiplication with number 9, I saw some patterns
arising and from that I have derived a code , which
will enable us to find the square of a group o af 9, 3
and 6s
Now read carefully . This is the basis for the coming
two or three classes .9 x 9 is 81, 9 X 11 x 99. So what
is 99 X 99 and the answer is 9801.999 X 999=998001
in this way if we calculate , then we can get the
answers for big numbers, avoiding the long
calculation.
Let us start now . 99 X 99 = 9801. How did we get it
so quickly. First count how many digits are there.
2digits on the multiplicand side and 2 on the
multiplier side. So totally 4 digits. For practice we
will put 4 dots ie. Two dots small gap and two dots.
We will take one 9 each from the unit position of
both sides and multiply . 9 x 9 is 81 so put 9 on the
unit position dot of the multiplicand side and 1 on
the unit position dot on the multiplier side . Here
we
have a special code to apply. It is One more One
less. one more than 8 is 9 so we'll put 9 beside 8
on the multiplicand side and one less than one is
zero so we will put zero beside one on the
multiplier side.Thus th answer is 9801.There are
other examples given. 999 X 999 = 998001 .
. What is the square of 9999. Here there are 8digits
totally. 4digit on the multiplicand side and 4 on the multiplier side. As taught earlier we will take 9 and
9 x 9 is 81 we will put dots first , ( - - - - - - - - -)
The we will place 8 on the unit position dot on the multiplicand side and one on the multiplier side unit position. Then remaining three dots on the
multiplicand side we will fill up with 9 since one
morethan 8 is 9. Same way One less than 1 is zero.
So fill
up 4 dots beside 1 in the multiplier side with zero.
Thus the answer is 999 8 0001. this is easy and
magical only if you remember the code.
Now I will show a little different calculation. Here the digits are not equal.eg 999× 99 .Here there are 3
digits on the multiplicand side and 2 on the multiplier side..We will arrange the dots into 3 groups. Centre
will be the extra 9s.on either side of it we will put
dots for multiplicand side and multiplier side. So in
this calculation one 9 is extra.We will put it in the
middle and do the calculation as earlier .The answer
is. 98 9 01.
99999 x 999 here two extra 9s. So the answer is
998 99 001.
We will study multiplication of 33x 99 , 666 x 999,
444 x 999 etc in the classes to follow.
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